Runga-Kutta Method using C

/*

Runga-Kutta Method
COmpute:: f(0.2)=?
When f(x,y)=x+y^2; y(0)=1 h=0.1
*/
#include<conio.h>
#include<stdio.h>

void main()
{
 float x,y,h,xf,k1,k2,k3,k4,n;
 int i;
 float f(float,float);
 printf("\nEnter x0 & y0");
 scanf("%f%f",&x,&y);
 printf("\nEnter x & h");
 scanf("%f%f",&xf,&h);
 n=(xf-x)/h;
 for(i=0;i<=(int)n;i++)
 {
 k1=h*f(x,y);
 k2=h*f(x+h/2,y+k1/2);
 k3=h*f(x+h/2,y+k2/2);
 k4=h*f(x+h,y+k3);
 y=y+(k1+2*(k2+k3)+k4)/6;
 x=x+h;
 }
 printf("\nResult %f",y);
 getch();
}
float f(float x,float y)
{
 return x+y*y;
}