#include<stdio.h>
void main()
{
int n,i,j,flag;
printf("\n\nEnter the limit\t:");
scanf("%d",&n);
printf("\nThe prime numbers within the given limit:\n");
for(i=1;i<=n;i++)
{
flag=0;
for(j=2;j<=i/2;j++)
{
if(i%j==0)
{
flag=1;
break;
}
}
if(flag==0)
printf("%d\t",i);
}
}
Tuesday, June 30, 2015
Sunday, June 28, 2015
Solve Quadratic Equation
#include <stdio.h>
#include <math.h>
void main()
{
float a,b,c,d,temp,r1,r2;
printf("\nEnter the value of a\t:");
scanf("%f",&a);
printf("Enter the value of b\t:");
scanf("%f",&b);
printf("Enter the value of c\t:");
scanf("%f",&c);
d=((b*b)-(4*c*a));
if(d==0)
{
printf("\nRoots are real and equal\n");
r1=-b/(2*a);
printf("\t X1=%f \n \t X2=%f ", r1, r1 );
}
else if(d>0)
{
printf("\nRoots are real and distinct\n");
temp=sqrt(d);
r1=(-b+temp)/(2*a);
r2=(-b-temp)/(2*a);
printf("\n\tX1=%f\n\tX2=%f",r1,r2);
}
else
{
printf("\nRoots are Imaginary\n");
d*=-1;
temp=sqrt(d);
r1=-b/(2*a);
r2=temp/(2*a);
printf("\n\tX1=(%f + %fi)\n\tX2=(%f - %fi)",r1,r2,r1,r2);
}
}
Output
Enter the value of a :1
Enter the value of b :-11
Enter the value of c :30
Roots are real and distinct
X1=6.000000
X2=5.000000
Find the greatest of two numbers using Conditional Operator
Sumit Kar June 28, 2015 Basic, Conditional Operator No comments
Generate the Fibonacci Series
#include<stdio.h>
void main()
{
int t,i,m=0,n=1,f=1;
printf("\n\nEnter the number of terms:");
scanf("%d",&t);
printf("\n The Fibonacci Series of %d terms:\n",t);
for(i=1;i<=t;i++)
{
printf("%d\t",f);
f=m+n;
m=n;
n=f;
}
}
Output
Enter the number of terms:10
The Fibonacci Series of 10 terms:
1 1 2 3 5 8 13 21 34 55
Check whether an alphabet is Vowel or not
#include <stdio.h>
void main()
{
char in;
printf("Enter Character: ");
scanf("%c", &in);
if(in>=65&&in<=90 || in>=97&& in<=122)
{
if(in<97)
in=in+32;
if(in=='a'||in=='e'||in=='i'||in=='o'||in=='u')
printf("vowel");
else
printf("consonent");
}
else
printf("Not an valid Alphabet");
}
Output
Enter Character: A
vowel
Print the ASCII values of all the English Alphabets
#include<stdio.h>
void main()
{
char chl='a';
char chu='A';
int i;
printf("\n===========================");
for(i=1;i<=26;i++,chu++,chl++)
printf("\n|%c | %d \t|| %c| %d |",chl,chl, chu, chu);
printf("\n===========================");
}
Output
===========================
|a | 97 || A| 65 |
|b | 98 || B| 66 |
|c | 99 || C| 67 |
|d | 100 || D| 68 |
|e | 101 || E| 69 |
|f | 102 || F| 70 |
|g | 103 || G| 71 |
|h | 104 || H| 72 |
|i | 105 || I| 73 |
|j | 106 || J| 74 |
|k | 107 || K| 75 |
|l | 108 || L| 76 |
|m | 109 || M| 77 |
|n | 110 || N| 78 |
|o | 111 || O| 79 |
|p | 112 || P| 80 |
|q | 113 || Q| 81 |
|r | 114 || R| 82 |
|s | 115 || S| 83 |
|t | 116 || T| 84 |
|u | 117 || U| 85 |
|v | 118 || V| 86 |
|w | 119 || W| 87 |
|x | 120 || X| 88 |
|y | 121 || Y| 89 |
|z | 122 || Z| 90 |
===========================
Friday, June 26, 2015
Find Area and Circumference of a Circle
#include<stdio.h>
#define PI 3.142
void main()
{
float r,a,c;
printf("\nEnter the radius of circle:\t");
scanf("%f",&r);
a=PI*r*r;
printf("\nThe area of the circle:\t%f",a);
c=2*PI*r;
printf("\nThe circumference of the circle: %f",c);
}
Output
Enter the radius of circle: 2
The area of the circle: 12.568000
The circumference of the circle: 12.568000
Enter the radius of circle: 1
The area of the circle: 3.142000
The circumference of the circle: 6.284000